(1/p)=((p+4)/(2p^2))-((1)/(2p))

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Solution for (1/p)=((p+4)/(2p^2))-((1)/(2p)) equation: 


D( p )

2*p = 0

p = 0

2*p^2 = 0

2*p = 0

2*p = 0

2*p = 0 // : 2

p = 0

p = 0

p = 0

2*p^2 = 0

2*p^2 = 0

2*p^2 = 0 // : 2

p^2 = 0

p = 0

p in (-oo:0) U (0:+oo)

1/p = (p+4)/(2*p^2)-(1/(2*p)) // - (p+4)/(2*p^2)-(1/(2*p))

1/p-((p+4)/(2*p^2))+1/(2*p) = 0

(-1*(p+4))/(2*p^2)+1/p+1/(2*p) = 0

(-1*2*p*p*(p+4))/(2*2*p*p*p^2)+(1*2*2*p*p^2)/(2*2*p*p*p^2)+(1*2*p*p^2)/(2*2*p*p*p^2) = 0

1*2*2*p*p^2-1*2*p*p*(p+4)+1*2*p*p^2 = 0

2*p^3+2*p^3-8*p^2 = 0

4*p^3-8*p^2 = 0

4*p^3-8*p^2 = 0

4*p^2*(p-2) = 0

p-2 = 0 // + 2

p = 2

4*p^2*(p-2) = 0

(4*p^2*(p-2))/(2*2*p*p*p^2) = 0

(4*p^2*(p-2))/(2*2*p*p*p^2) = 0 // * 2*2*p*p*p^2

4*p^2*(p-2) = 0

( 4*p^2 )

4*p^2 = 0 // : 4

p^2 = 0

p = 0

( p-2 )

p-2 = 0 // + 2

p = 2

p in { 0} 

p = 2

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